If capacitors of 10 mfd, 5 mfd, and 5 mfd are wired in series, what is the total capacitance in mfd?

When capacitors are wired in series, the total capacitance can be calculated using the formula for capacitors in series, which is:

[

\frac{1}{C_{\text{total}}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3}

]

In this case, you have three capacitors with values of 10 mfd, 5 mfd, and 5 mfd. Plugging these values into the series capacitance formula gives:

[

\frac{1}{C_{\text{total}}} = \frac{1}{10} + \frac{1}{5} + \frac{1}{5}

]

To combine the fractions, you'll first convert them to a common denominator:

[

\frac{1}{10} + \frac{2}{10} + \frac{2}{10} = \frac{5}{10} = \frac{1}{2}

]

Now, taking the reciprocal to find the total capacitance:

[

C_{\text{total}} = \frac{1}{\frac{1}{2}} = 2 \text{ m